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Physics (Work and Energy) Help please? ?
A 3.00kg piece of wood slides on the surface shown in the accompanying figure. All parts of the surface are frictionless, except for a 30.0m -long rough segment at the bottom, where the coefficient of kinetic friction with the wood is 0.200. The wood starts from rest 5.00m above the bottom.
Questions:
1)Where will the wood eventually come to rest?
2)How much work is done by friction by the time the wood stops?
I have no idea what equations to use although I suspect something along the lines of conservation of energy and the work energy theorem.
Please help with how to solve this problem.
1. You start with the equation for frictional force and convert it to work
F=uN (u is the coefficient of friction and N is the normal force, which I'm assuming is mg)
W=uxN=uxmg
conservation of energy for work
W=K --> W=U --> uxmg=mgy --> ux=y --> x=y/u=5.00m/.200=25.0m
2. You start with conservation of energy U=K where all of the potential energy at the top (5.00m) is converted to kinetic energy at the bottom.
mgy=U=3.00gk*9.81m/ss*5.00m=147 J